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Current divider calculator

How current splits between parallel resistors — the mirror image of the voltage divider.

Current through R1I × R2/(R1+R2) — the OTHER branch's resistance on top75.0 mA
Current through R2I × R1/(R1+R2)25.0 mA
Parallel resistanceR1∥R2 — what the source actually sees75 Ω
Voltage across the pairsame across both branches — that's WHY current divides this way7.50 V

How it works

Parallel branches share one voltage. Ohm's law then fixes each branch's current: I_branch = V/R_branch. Express V as I_total × (R1∥R2) and the divider falls out: I1 = I × R2/(R1+R2). The inverse proportionality is the whole lesson — and the reason a fat copper trace in parallel with your shunt resistor quietly ruins a current measurement.

Common questions

Why is the OTHER resistor on top of the fraction?

Both branches see the same voltage, so the branch with LESS resistance takes MORE current — division is inverse. I1 = I × R2/(R1+R2): R2 in the numerator because R1's share grows as R2 grows. It's the exact mirror of the voltage divider, where your own resistor sits on top.

Does 'current takes the path of least resistance' mean it all goes one way?

No — that phrase is folklore. Current takes EVERY path, in inverse proportion to resistance. A 1 Ω path in parallel with a 1 kΩ path still sends ~0.1% through the 1 kΩ. The only time all current takes one path is when the other is truly open.

What about three or more branches?

Same principle through conductances: each branch takes G_branch/G_total of the current, where G = 1/R. For two branches that algebra simplifies to the R2/(R1+R2) form; for more, work in conductances — it stays one line.

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